Thinking about doubling-up on wheels...

The

torque moment on the axle is: T = (d)(F)

If we say the BX wheel is "X" in width and also about the same distance from the internal transmission bearing, the distance from the bearing is 2X, and the torque calculation is (2X)(F).

By adding another wheel and rolling over a rock with the outside wheel the torque on the axle would be: (3/2X)(F), effectively a 50% increase over the design. Probably not a good idea.

If the rear tire is 18" wide we divide that by 2 so the weight is in the center of the tire, and add 18" if we assume the inside edge of the tire is 18" from the internal bearings:

(18" / 2) + 18" = 27"

If the three point hitch is carrying 500# and the rear end mass of the tractor is 1/3 the tractor weight (1,410# * 1/3), the weight on each of two rear axles is:

(500# + 470#) / 2 = 485#

The torque is:

(27")(1 foot / 12") (485#) = 1,090 ft*lbs

Adding 4" spacers:

(27" + 4")(1 foot / 12") (485#) = 1,252 ft*lbs

((1,252ft*lbs / 1,090ft*lbs) -1) * 100% =

**15% increase** (or thereabouts)

(which is simply: (4"/27")(100%) = 15%

To stay within Kubota specifications for the BX2370, carry 15% less weight less than the maximum capacity.

Three point hitch. Max.lift force 24 in. behind lift points: 680 lbs

(680 lbs)(85%) = 578#

The heaviest thing I carry is the WoodMaxx MX-8600 Chipper which specs. at 580#. so...with Pat's Quick Hitch and the chipper center of mass likely being more than 24" behind the lift points it's a consideration to use 2" spacers (or at least treat the tractor gently with 4" spacers).

Who said, "Use math????"